Last official estimated population of Roman Forest town (Montgomery County**, Texas state) was 1,814 (year 2014)[1]. This was 0.001% of total US population and 0.01% of total Texas state population. Area of Roman Forest town is 1.5 mi² (=3.9 km²)[6], in this year population density was 1,204.52 p/mi². If population growth rate would be same as in period 2010-2014 (+4.21%/yr), Roman Forest town population in 2026 would be 2,976*.
Historical population of Roman Forest town for period 1980-2014:
Estimated population for 2014[1]. Click on flag to hide it.
Population • Legends • Position

[1980-1990] +0.84 %/yr
[1990-2000] +2.91 %/yr
[2000-2005] +1.13 %/yr
[2005-2010] +1.57 %/yr
[2010-2014] +4.21 %/yr
• Humble city population
14.7 mi,
205°
• Cleveland city
11.6 mi,
17°
• Oak Ridge North city
17 mi,
264°
• Splendora city
3.4 mi,
356°
• Patton Village city
1.2 mi,
343°
• Woodbranch city
1.4 mi,
274°
• Cut and Shoot city
15.4 mi,
314°
• Plum Grove city
4.1 mi,
69°
• North Cleveland city
13.1 mi,
15°
• Woodloch town
15.4 mi,
279°
*Calculated by population.us from last known population growth rate, not official data.
**Some cities are placed on more than one county. Only 1 county is shown.
[1] Cities and Towns (Incorporated Places and Minor Civil Divisions) 2014, archived from the original, retrieved 02/23/2016
[2] City and Town Intercensal Estimates (2000-2010), archived from the original, retrieved 02/23/2016
[3] Places: 1990 and 1999 Populations, With Numeric and Percent Population Change, archived from the original, retrieved 02/23/2016
[4] Population of the 100 Largest Urban Places: 1980,
[5] Population of the 100 Largest Urban Places in history,
[6] Area, latitude longitude data, retrieved 02/23/2016
[7] Through the Decades, Overview 1790-2010, PDF, large files! >100 Mb
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