Last official estimated population of Slaughterville town (Cleveland County**, Oklahoma state) was 4,210 (year 2014)[1]. This was 0.001% of total US population and 0.11% of total Oklahoma state population. Area of Slaughterville town is 38.8 mi² (=100.4 km²)[6], in this year population density was 108.61 p/mi². If population growth rate would be same as in period 2010-2014 (+0.44%/yr), Slaughterville town population in 2025 would be 4,417*.
Historical population of Slaughterville town for period 1980-2014:
Estimated population for 2014[1]. Click on flag to hide it.
Population • Legends • Position
[1980-1990] +2.45 %/yr
[1990-2000] +3.75 %/yr
[2000-2005] +1.29 %/yr
[2005-2010] +1.54 %/yr
[2010-2014] +0.44 %/yr
• Norman city population
10.7 mi, 340°
• Noble city
5.8 mi, 300°
• Purcell city
7.4 mi, 224°
• Lexington city
6.1 mi, 209°
• Goldsby town
11 mi, 281°
• Wayne town
12.4 mi, 188°
• Washington town
12.1 mi, 256°
• Tribbey town
10 mi, 86°
• Etowah town
6.7 mi, 71°
• Rosedale town
13.3 mi, 155°
*Calculated by population.us from last known population growth rate, not official data.
**Some cities are placed on more than one county. Only 1 county is shown.
[1] Cities and Towns (Incorporated Places and Minor Civil Divisions) 2014, archived from the original, retrieved 02/23/2016
[2] City and Town Intercensal Estimates (2000-2010), archived from the original, retrieved 02/23/2016
[3] Places: 1990 and 1999 Populations, With Numeric and Percent Population Change, archived from the original, retrieved 02/23/2016
[4] Population of the 100 Largest Urban Places: 1980,
[5] Population of the 100 Largest Urban Places in history,
[6] Area, latitude longitude data, retrieved 02/23/2016
[7] Through the Decades, Overview 1790-2010, PDF, large files! >100 Mb
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