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```
#' @title Summary of the division rules
#' @description This function returns the awards vectors selected, for a given claims problem, by the rules: AA, APRO, CE, CEA, CEL, DT, MO, PIN, PRO, RA, and Talmud.
#' @param E The endowment.
#' @param d The vector of claims.
#' @param draw A logical value.
#' @return A data-frame with the awards vectors selected by the main division rules. If draw = TRUE,
#' a bar chart for each claimant representing the amounts that the claimant receives.
#' @details Let \eqn{E\ge 0} be the endowment to be divided and \eqn{d\in \mathcal{R}^n}{%
#' d} the vector of claims with \eqn{d\ge 0} and such that \eqn{\sum_{i=1}^{n} d_i\ge E,\ }{}
#' the sum of claims exceeds the endowment.
#'
#' A vector \eqn{x=(x_1,\dots,x_n)}{x=(x1,...,xn)} is an awards vector for the claims problem \eqn{(E,d)} if:
#' no claimant is asked to pay (\eqn{0\le x});
#' no claimant receives more than his claim (\eqn{x\le d});
#' and the balance requirement is satisfied, that is, the sum of the awards is equal to the endowment (\eqn{\sum_{i=1}^{n} x_i= E}{x1+...+xn=E}).
#'
#' A rule is a function that assigns to each claims problem \eqn{(E,d)} an awards vector for \eqn{(E,d)},
#' that is, a division between the claimants of the amount available.
#'
#' The formal definitions of the main rules are given in the corresponding function help.
#' @seealso \link{AA}, \link{APRO}, \link{CD}, \link{CE}, \link{CEA}, \link{CEL}
#' , \link{DT}, \link{MO}, \link{PIN}, \link{PRO}, \link{RA}, \link{Talmud}, \link{verticalruleplot}
#' @examples
#' E=10
#' d=c(2,4,7,8)
#' allrules(E,d)
#' @references Mirás Calvo, M.A., Quinteiro Sandomingo, C., and Sánchez-Rodríguez, E. (2020). The core-center rule for the bankruptcy problem. Working paper 2020-02, ECOBAS.
#' @references Thomson, W. (2019). How to divide when there isn't enough. From Aristotle, the Talmud, and Maimonides to the axiomatics of resource allocation. Cambridge University Press.
#' @importFrom graphics par
#' @importFrom graphics barplot
#' @export
allrules = function(E, d, draw = TRUE) {
n = length(d) #The number of claimants
D = sum(d) # The sum of claims
########################################
# Required: (E,d) must be a claims problem, i.e., E >=0, d >=0, E <= sum(d)
########################################
if (E < 0 || sum((d < 0)) > 0 || E > D)
stop('(E,d) is not a claims problem.')
######### THE 11 RULES ###################
CEL = CEL(E, d)
CE = CE(E, d)
MO = MO(E, d)
PRO = PRO(E, d)
APRO = APRO(E, d)
RA = RA(E, d)
AA = AA(E, d)
Talmud = Talmud(E, d)
PIN = PIN(E, d)
CEA = CEA(E, d)
DT = DT(E, d)
########## THE TABLE ######################
names = c("AA", "APRO", "CE", "CEA", "CEL", "DT", "MO", "PIN", "PRO", "RA","Talmud")
table = data.frame(rbind(AA, APRO, CE, CEA, CEL, DT, MO, PIN, PRO, RA,Talmud))
claimants = rep(0, n)
for (i in 1:n) {
claimants[i] = c(toString(i, 0))
}
colnames(table) = c(claimants)
if (draw == TRUE){
########### THE BAR GRAPH ################
if(n==2){
par(mfrow = c(2, 1))
for (i in 1:n) {
barplot(table[, i],
names.arg = names,
main = paste("Claimant", i))
}
} else if(n==3|n==4){
par(mfrow = c(2, 2))
for (i in 1:n) {
barplot(table[, i],
names.arg = names,
main = paste("Claimant", i))
}
} else if(n==5|n==6){
par(mfrow = c(3, 2))
for (i in 1:n) {
barplot(table[, i],
names.arg = names,
main = paste("Claimant", i))
}
} else if(n==7|n==8|n==9){
par(mfrow = c(3,3))
for (i in 1:n) {
barplot(table[, i],
names.arg = names,
main = paste("Claimant", i))
}
} else {
par(mar = rep(3, 4))
par(mfrow = c(3, 4))
for (i in 1:n) {
barplot(table[, i],
names.arg = names,
main = paste("Claimant", i))
}
}
}
on.exit(par(mfrow = c(1, 1)))
return(table)
}
```

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