Last official estimated population of Lake Alfred city (Polk County**, Florida state) was 5,253 (year 2014)[1]. This was 0.002% of total US population and 0.03% of total Florida state population. Area of Lake Alfred city is 13.2 mi² (=34.2 km²)[6], in this year population density was 398.14 p/mi². If population growth rate would be same as in period 2010-2014 (+1.17%/yr), Lake Alfred city population in 2024 would be 5,899*.
Historical population of Lake Alfred city for period 1920-2014:
Estimated population for 2014[1]. Click on flag to hide it.
Population • Legends • Position
[1920-1930] +7.09 %/yr
[1930-1940] +3.88 %/yr
[1940-1950] +3.28 %/yr
[1950-1960] +5.6 %/yr
[1960-1970] +2.65 %/yr
[1970-1980] +0.97 %/yr
[1980-1990] +1.37 %/yr
[1990-2000] +1.26 %/yr
[2000-2005] +2.37 %/yr
[2005-2010] +1.84 %/yr
[2010-2014] +1.17 %/yr
• Lakeland city population
14.3 mi, 257°
• Winter Haven city
3.7 mi, 187°
• Haines City city
6.7 mi, 83°
• Lake Wales city
14.5 mi, 148°
• Auburndale city
4.1 mi, 271°
• Dundee town
9.3 mi, 127°
• Davenport city
8.2 mi, 58°
• Eagle Lake city
8.7 mi, 192°
• Polk City town
8.5 mi, 311°
• Lake Hamilton town
6.9 mi, 119°
*Calculated by population.us from last known population growth rate, not official data.
**Some cities are placed on more than one county. Only 1 county is shown.
[1] Cities and Towns (Incorporated Places and Minor Civil Divisions) 2014, archived from the original, retrieved 02/23/2016
[2] City and Town Intercensal Estimates (2000-2010), archived from the original, retrieved 02/23/2016
[3] Places: 1990 and 1999 Populations, With Numeric and Percent Population Change, archived from the original, retrieved 02/23/2016
[4] Population of the 100 Largest Urban Places: 1980,
[5] Population of the 100 Largest Urban Places in history,
[6] Area, latitude longitude data, retrieved 02/23/2016
[7] Through the Decades, Overview 1790-2010, PDF, large files! >100 Mb
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